# SB vs SHC BB

• Bronze
Joined: 04.03.2005
I today did some math about sb vs SHC and the result was quite interesting:
We can actually raise any two in the SB if he only defends the 12% that SHC would allow him if we lose less than 5,5 big bets when he doesn't fold.
Calculation:
0,88*(0,75bb) = 0,66bb
0,88 is the percentage with which villain folds and 0,75 sb is the win SB+BB

0,66bb-0,12x = 0 // calculating when it is break even
x = -5,5bb

is this correct and is the number of -5,5bb realistic?
i think it is easily especially given that very often they will fold the best hand ( a high) when we make a continuation bet on the flop.
So if you can spot someone who plays that tightly in the BB the raise any two ought to be profitable.
Thoughts appreciated.

edit: i made a little mistake which makes the decision even easier!
• 2 replies
• Bronze
Joined: 24.01.2006
Yap we are aware of that problem and are working on an ecotonal solution between SHC and ORC with more Blind Defence elements also we want to implement an extra Basic Blind Defence article.
• Bronze
Joined: 14.01.2005
Generally, the SHC does a terrible job with regards to blind defense.