# Pot odds once and forever

• Bronze
Joined: 27.01.2008
Ok I just have a question about calculating pot odds that I would like to settle once and for all. The thing is that I've read numerous articles regarding this topic or other topics where there was also calculation of pot odds included, but still see different ways to calculate them (whether because the author belives his way is correct or because they make a mistake).

So, example:

Pot size: 10\$
Opponent bets 5\$

A) We have to pay 5\$ to win 20\$ (1:4 pot odds)

B) We have to pay 5\$ to win 15\$ (1:3 pot odds)

Which one?
• 7 replies
• Bronze
Joined: 22.11.2009
B
• Bronze
Joined: 13.01.2010
Originally posted by jbpatzer
B
• Bronze
Joined: 09.06.2010
B - because other wise we would be saying if you choose A - "i have to call \$5 to break even" rather than B which would be " i have to call \$5 to make profit"
• Bronze
Joined: 14.05.2010
pot odds B, but when converting that into equity you will have to win not 33% of times, but only 25% to be break even
• Bronze
Joined: 27.01.2008
Originally posted by phantommm92
pot odds B, but when converting that into equity you will have to win not 33% of times, but only 25% to be break even
Ok thanks.

So basically, pot odds: need to pay 5\$ to win 15\$ --> 1:3 pot odds (1win:3loss to be breakeven) --> 1/4 --> 25%
• Bronze
Joined: 30.08.2010
I wonder how noone came with C .

B anyway
• Bronze
Joined: 03.10.2010
ah this has answered one of my questions too. Cheers!