• Bronze
Joined: 28.01.2010
Hi guys!

Today we played live poker.

I called raise pre with 42s on BTN (it was only 3-handed, vs 1 fish in the hand)
and flop came down: 444 (LOLzzz ) just 1st time flopped quads in live game, thats why Im a bit surprised/excited (I only play poker very rare now btw)

Whats the odds of flopping quads with only one card in your hand???

p.s.
I got it in vs that fish for his all stack (he turned a full house, with 5 on turn)
• 11 replies
• Bronze
Joined: 21.04.2011
3/48 * 2/47 * 1/46 is the probability i think
• Bronze
Joined: 17.05.2009
9799-1
• Bronze
Joined: 21.07.2009
Originally posted by needagun
3/48 * 2/47 * 1/46 is the probability i think
Huh? Something tells me that we don't flop quads once every 46 hands
• Bronze
Joined: 21.04.2011
that's 6/(48*47*45)
• Bronze
Joined: 03.10.2007
Originally posted by needagun
3/48 * 2/47 * 1/46 is the probability i think
*2
• Bronze
Joined: 21.07.2009
Originally posted by Wriggers
Originally posted by needagun
3/48 * 2/47 * 1/46 is the probability i think
Huh? Something tells me that we don't flop quads once every 46 hands
Epic misread fail on my part. No wonder I went to bed shortly after this post.
• Bronze
Joined: 29.03.2010
easy game, gratz
• Bronze
Joined: 16.06.2010
Originally posted by miljonszalie
Hi guys!

Today we played live poker.

I called raise pre with 42s on BTN (it was only 3-handed, vs 1 fish in the hand)
and flop came down: 444 (LOLzzz ) just 1st time flopped quads in live game, thats why Im a bit surprised/excited (I only play poker very rare now btw)
What kind of poker game is that if you call a raise on the button in a 3 handed table?
• Bronze
Joined: 08.05.2009
First card on flop can be any of the six cards that match one of your two:
6/50

Second card must be one the remaining two that match the paired card and make trips:
2/49

Third card must be last remaining card to make the 4 of a kind:
1/48

So by multiplying these, the probability is:

(6*2*1)/(50*49*48)

=1/(50*49*4)

=1/(200*49)

=1/9800

Or 9799-1 against, as LONGPLAY66 said above.

Rob
• Bronze
Joined: 07.08.2011
You have 6 possible cards for a pair, then two cards for that pair to become tree of a kind and one for quads.
There are 50 unknown cards remaining, then 49 and 48.

The chance is 6/50 * 2/49 *1/48 = 1/9800, so one time every 9800 (unpaired) hands.
• Bronze
Joined: 01.11.2008
What kind of poker game is that if you call a raise on the button in a 3 handed table?

Only 1 blind?