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The Profit Equation

    • arjun2001
      arjun2001
      Bronze
      Joined: 28.03.2008 Posts: 352
      Hey everyone I wanted to ask any people good at maths out there. Lets say I wanted to build a bankroll throough heads up sit and gos.

      What will be the equation for the avergae profit. For example I play 100 games, and win 52 games and lose 48. Since in these matches you win less and lose more because of the rake buy in.

      $2.00+$0.20(rake fee) Win= $4(total)
      $2.00+0.20(rake fee) Lose= $2.20

      Any help is appreciated. Even if you cannot come with an equation just tell me an easier way to do this. So I know how many to play every day and how many to in to make profit.

      Thanks in advance. ;)
  • 4 replies
    • chenny8888
      chenny8888
      Bronze
      Joined: 03.10.2007 Posts: 19,324
      wins*profitperwin-losses*profitperloss
      divided by
      total games

      in this case...

      (52*1.8$-48*2.2$)/100

      or...

      93.6$-105.6$/100
      -12$/100
      or average profit of -.12$ per game (you on average lose 12 cents per game)
    • arjun2001
      arjun2001
      Bronze
      Joined: 28.03.2008 Posts: 352
      thanks
    • goliat80
      goliat80
      Bronze
      Joined: 01.04.2008 Posts: 31
      You could say that with an 10% rake you need to win atleast 55% of heads up to brake even or make money.

      Depending on the amount of rake taken.... I have seen tables with 1 +0,25 thats 25 % rake, on theese tables you need to win 62,5% of the heads up matches to brake even or even win money.
    • arjun2001
      arjun2001
      Bronze
      Joined: 28.03.2008 Posts: 352
      $1 are 9 player sit and goes not heads up (I think). Yea that way works too. I am not really looking forward to heads up anymore looking at the winning percentage and the player I am.