# The Profit Equation

• Bronze
Joined: 28.03.2008
Hey everyone I wanted to ask any people good at maths out there. Lets say I wanted to build a bankroll throough heads up sit and gos.

What will be the equation for the avergae profit. For example I play 100 games, and win 52 games and lose 48. Since in these matches you win less and lose more because of the rake buy in.

\$2.00+\$0.20(rake fee) Win= \$4(total)
\$2.00+0.20(rake fee) Lose= \$2.20

Any help is appreciated. Even if you cannot come with an equation just tell me an easier way to do this. So I know how many to play every day and how many to in to make profit.

• 4 replies
• Bronze
Joined: 03.10.2007
wins*profitperwin-losses*profitperloss
divided by
total games

in this case...

(52*1.8\$-48*2.2\$)/100

or...

93.6\$-105.6\$/100
-12\$/100
or average profit of -.12\$ per game (you on average lose 12 cents per game)
• Bronze
Joined: 28.03.2008
thanks
• Bronze
Joined: 01.04.2008
You could say that with an 10% rake you need to win atleast 55% of heads up to brake even or make money.

Depending on the amount of rake taken.... I have seen tables with 1 +0,25 thats 25 % rake, on theese tables you need to win 62,5% of the heads up matches to brake even or even win money.
• Bronze
Joined: 28.03.2008
\$1 are 9 player sit and goes not heads up (I think). Yea that way works too. I am not really looking forward to heads up anymore looking at the winning percentage and the player I am.