• Bronze
Joined: 22.06.2008
I was looking at the quiz here

http://www.pokerstrategy.com/strategy/sng/613/2/

and I got question #4 wrong and I think it's written wrong.

QUESTION 4: You have top-pair kings. There are also two queens on the board. Can you count the pair of queens towards your pair of kings, thus can you assume you hold two pairs?

How does that make anysense?

If I'm holding KK
and my opponent is holding 9 - 10

and let's say the board is Q-Q-9-10-2

from what I know I'm holding Kings and Queens and my opponent is holding Queens and 10's

Am I wrong?
• 6 replies
• Bronze
Joined: 11.12.2007
You don't count paired board as your own pair. because the other player also has that pair
• Bronze
Joined: 20.02.2008
Hello VinDoGG,

I agree that the question is not well formulated. I will look into making the question and explanation clearer.

Look here: http://www.pokerstrategy.com/strategy/no-limit/824/2/ for how it is actually meant.

Best regards,
SoyCD
• Bronze
Joined: 22.06.2008
So based on my scenario are you telling me if I hold KK and the board shows Q-Q-10-9-2 and my opponent holds 9-10. My opponent would win?
• Bronze
Joined: 20.02.2008
No he wouldn't - you are holding KK and QQ and he is holding QQ and TT (his 99 is forfeit).

The article is simply trying to make players aware that there is a difference between having two pairs and two pair when the board is paired (since often - especially against multiple players - one opponent will be holding trips)

Best regards,
SoyCD
• Bronze
Joined: 22.06.2008
Ok thanks! looking at the comments I'm glad I'm not the only one that found it confusing.
• Bronze
Joined: 13.01.2008
Originally posted by SoyCD
Look here: http://www.pokerstrategy.com/strategy/no-limit/824/2/ for how it is actually meant.
Thank you, thank you. It's nothing, really... just doing my job.