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SB vs SHC BB

    • Blinzler
      Blinzler
      Bronze
      Joined: 04.03.2005 Posts: 7,456
      I today did some math about sb vs SHC and the result was quite interesting:
      We can actually raise any two in the SB if he only defends the 12% that SHC would allow him if we lose less than 5,5 big bets when he doesn't fold.
      Calculation:
      0,88*(0,75bb) = 0,66bb
      0,88 is the percentage with which villain folds and 0,75 sb is the win SB+BB

      0,66bb-0,12x = 0 // calculating when it is break even
      x = -5,5bb

      is this correct and is the number of -5,5bb realistic?
      i think it is easily especially given that very often they will fold the best hand ( a high) when we make a continuation bet on the flop.
      So if you can spot someone who plays that tightly in the BB the raise any two ought to be profitable. :D
      Thoughts appreciated.

      edit: i made a little mistake which makes the decision even easier!
  • 2 replies