Originally posted by justkyle88
holy shit, how did u get that number?
I assume you meant you want to know the odds of two absolutely identical flops coming in direct sequence. Let's say that you want to know the odds of T
T
T
falling twice in a row. The odds of T
being the first card is 1/52. There are 51 cards left, so the odds of T
falling equals 1/51, and consequently T
's odds are 1/50. So the odds of that flop are 1/(52*51*50).
The odds of the same flop falling twice are then [1/(52*51*50)] * [1/(52*51*50)] or simplified 1/(52*51*50)^2. Worked out, this equals 1/17,582,760,000 or the number I posted earlier.
Of course, the above calculation assumes that the first of the two flops hasn't been dealt yet. If the flop you're looking at is T
T
T
, the odds of the next one being identical is only 1/(52*51*50) or 0,000754%.
T
T
falling twice in a row. The odds of T
