A Little Help - Part 1

  • MTT
  • MTT
  • $16
  • Fullring
(16 Votes) 10134


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In this new series Byron and Jonathan introduce you a new and interesting review format. Byron recorded a $16 Superturbo Rush Tournament he played with commentary then sent it to Jonathan who added his comments. This way the two coaches can go through their entire thought process without interrupting and analyse each spot individually.


A Little Help littlehelp Multicoach Rush superturbo turbo

Comments (22)

newest first
  • FishermansFriend


    Enjoy this new special video!

    Please keep the comments in Englsih!
  • sirilidion


    what I always get in trouble with understanding these multi -opponent calculations that is wouldn't make sense if they have a wide range for example 5 opponents behind they all shove 21 % so you get reraised 5 * 21 % 104 % ??? which obviously isn't possible
  • sirilidion


    105 % :( sorry
  • goldchess


    don't let jbpatzer see that calculation :P
  • sirilidion


    I would usely take the different route of calculation how much they fold then so that would by 0.79^5 =30.8 % so you would be raised off your hand in 69.2 % still I am not exactly sure when I should use the raise amount or the fold amount and if this is correct in the first place?
  • taschendamenfalter


    very good concept in this vid - thx to both of you


    nice format
  • dydukas


    OMG. I raise with 50% range, it means probability of me raising twice in a row is 250%, according to 5*21% "logic". :D
  • ByronJacobs


    The right way to make the calculation as to whether you’re likely to get called with multiple opponents is to work out 1 – (the chance that nobody calls). In the specific instance at the end of the video we give the calling ranges as 6.3% and there are 5 opponents. The chance that a specific opponent doesn’t call is obviously 1 – 0.063 = 0.937. So the chance that all five don’t call is 0.937 ^ 5 = 0.72. Therefore the chance that you get called is 1 – 0.72 = 0.28.

    This isn’t completely accurate as occasionally you get called in more than one spot but the above calculation is certainly good enough for practical considerations.
  • chiller666


    the calculation is not quite correct.
    as calculated, 105% mean here, that on average 1.05 people behind you have a hand from there shoving-range.
    If you would calculate the folding like this, you would get 79% * 5 = 395%, meaning that on average 3.95 people fold, what equals 1.05 people shoving.
    What you wrote in #5 is correct
  • max8989


    Cool! :)
  • phantommm92


    really nice format, loved it
  • luckexpress


    JohnathanLittle explain very well!
  • BillGatesIII


    Well done:)
  • i5bet72o


    ya pokertracker works for these tourneys, i also love these tourneys, they are so much fun
  • i5bet72o


    no way he shoves as wide as johanthan little said in poker stove imo
  • PhantomR32


    Wow you really used a calculator for 61+46 / 2... Shocking!
    Other than that, good video!
  • pikili


    remember keep the komments in Englsih!
  • Harnas31


    well done
  • bj355


    LOL massive overshove for 10x your raise?
  • JonathanLittle


    I use numerous shortcuts on the fly in ordere to make quick calculations at the table. While they are not 100% accurate, they are close enough to work. Poker is basically a guessing game. If you know all the math away from the table but cant do it in 30 seconds at the table, it is useless. Find the difficulty of math that works for you and use it.
  • gavinonymous


    What is the correct way to calculate the chance of several players calling?

    Using root mean square: if 5 players after you have a 10% calling range (for simplicity) we get sqrt(0.1^2+0.1^2 etc..) = 22% chance of being called by at least one player.

    if it's 15%, 10%, 10%, 5% snd 5% we'd also get about 22% using RMS instead of 45% .. a significant difference.