Implied odds

You played it great.

I would fold on the turn.

Im not sure if I get your question right.
You ask for implied odds for hitting one of the 2 outs that you have, to stack off a flush or a queen with a full house?

That is

Amount to win on later streets = (1/eq*C)-(P+C)
eq = equity to hit to the nuts
C = amount to call
P = pot at the time of calling

In your example it means you need to get on average $35 on the river to make a call profitable.

On the pro side there is, that you are in position and you are both deep.
On the con side there is, that the pot is very small, that villain will not pay the hole stack if he doesn't have the nut flush draw and that even this is arguable since the board is paired.
Also one of the 2 Ts mabe even can't count as out, since 1 T is in spades. In these cases only Ks will pay you.
I don't think villain will play for stacks with a mid flush.

It could also be possible that villain only has a weak A or something. Then we will get paid even worse.

Then on the other side, maybe even a small pocket could play like this, and sometimes the river goes x/x and you are good at showdown.

There are sooo many factor to be count in, in this damned implied odds thing, that I think both options are fine.
Despite the price on the turn is soooo cheap, I think folding could be slightly more correct. But I think at the table I would have called.